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> I gather you were powering the camera through an auxiliary socket and
> not through the battery compartment. I hope you didn't apply the full
> 13.8 volts to the camera; I thought they ran on a 7.2 volt Li-ion?
Actually, I did just that. Canon's 1D cameras all come with an
adapter that looks like an NP-E3 battery, but with a small plug on the
outside. Into this you plug a cord from a wallwart that produces
13.5V (measured). I just chopped the cord off the wallwart and
connected it to a normal 13.8V P/S through an ammeter.
> Also, powering through an auxiliary port may involve shunt circuitry or
> bleed resistance within the camera to prevent a no-load supply from
> rising above 7.2 volts.
The output of this adaptor is equal to its input (13.5V). But what
you say is in fact the case: even when not plugged into the camera,
this adapter consumes 19mA. Probably a diode. So from all of the
current figures I gave, one should subtract 19mA. Unfortunately, this
is semi-disturbing news to people who may think to power their camera
via an external battery through this adapter (e.g., Digital Camera
Battery etc). A quarter watt of power is being sucked down, even when
the camera is "off".
Colin_D - 12 Feb 2007 21:01 GMT
>> I gather you were powering the camera through an auxiliary socket and
>> not through the battery compartment. I hope you didn't apply the full
[quoted text clipped - 18 lines]
> Battery etc). A quarter watt of power is being sucked down, even when
> the camera is "off".
Ok, solved. Good.

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Roger N. Clark (change username to rnclark) - 13 Feb 2007 05:02 GMT
>>I gather you were powering the camera through an auxiliary socket and
>>not through the battery compartment. I hope you didn't apply the full
[quoted text clipped - 18 lines]
> Battery etc). A quarter watt of power is being sucked down, even when
> the camera is "off".
Thanks for the info.
Roger