Photo Forum / Digital Photography / DSLR Cameras / July 2006
How to Calculate Zoom
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Dave - 13 Jun 2006 01:09 GMT Looking a purchasing a new zoom lense for a rebel xt. I see some lenses with a 4X or ~7X zoom equil. How do you calculate the ?X zoom factor for a zoom lense?
thanks
Jeremy Nixon - 13 Jun 2006 01:17 GMT > Looking a purchasing a new zoom lense for a rebel xt. I see some lenses > with a 4X or ~7X zoom equil. How do you calculate the ?X zoom > factor for a zoom lense? Maximum focal length divided by minimum focal length.
Most SLR lenses aren't rated that way, though. They usually just give the actual focal length numbers, which are a lot more meaningful.
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Marc Sabatella - 13 Jun 2006 01:25 GMT > Looking a purchasing a new zoom lense for a rebel xt. I see some > lenses with a 4X or ~7X zoom equil. ??? This is not how lenses for SLR's are usually labelled. They are labelled with the actual focal length range: 18-55, 70-300, 28-80, etc. A lens with a range of 18-55 means its focal length is 18mm when zoomed "in" and 55mm when zoomed "out". If you wanted to calculate a single number to say how much more magnification you can get when zoomed "out" versus "in", simply divide. The 18-55 lens that usually comes with the camera is basically a 3X zoom. But then, so is a 100-300 zoom - just when in which even zoomed "in" provides more magnification than the former lens is zoomed "out". A point & shoot camera with a 3x zoom is likely to be similar to the 18-55 in terms of what focal lengths it is providing.
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Gerrit 't Hart - 13 Jun 2006 02:32 GMT > > Looking a purchasing a new zoom lense for a rebel xt. I see some > > lenses with a 4X or ~7X zoom equil. [quoted text clipped - 10 lines] > likely to be similar to the 18-55 in terms of what focal lengths it is > providing. Have I had it wrong all these years?
I have always believed that "zooming in" means that you magnify the picture. To do that you use the larger focal length number end of the zoom lens. So on a 28 - 200 lens zoomed "in" would be at the 200mm end of the zoom.
Gerrit
Marc Sabatella - 13 Jun 2006 19:04 GMT > Have I had it wrong all these years? > > I have always believed that "zooming in" means that you magnify the > picture. Actually, in that context, that's how I would use the term too. But here I was thinking more of the physical action of the lens - one "zooms in" on a scene in the sense you mean by twisting the zoom ring to make the lens extend "out" from the camera. In any case, the term isn't really a technical one, nor is the idea of computing a "zoom ratio factor" one that ordinarily concerns SLR photographers - we're generally more concerned with the specific focal lengths than what the ratio of biggest to smallest is. But in a point & shoot world, where it's assume that all cameras will zoom from some sort of wide angle to some sort of telephoto, and in which differing sensor sizes make specific focal length numbers meaningless for comparison purposes (unless converted to 35mm equivalents), it is of course a very common marketing metric.
--------------- Marc Sabatella marc@outsideshore.com
Music, art, & educational materials Featuring "A Jazz Improvisation Primer" http://www.outsideshore.com/
Jeff Rife - 13 Jun 2006 20:20 GMT Marc Sabatella (marc@outsideshore.com) wrote in rec.photo.digital.slr-systems:
> But > here I was thinking more of the physical action of the lens - one "zooms > in" on a scene in the sense you mean by twisting the zoom ring to make > the lens extend "out" from the camera. Although this is the way it works for probably 99% of zoom lenses, I have a Sigma 24-70/f2.8 that is shortest at 60mm. It lengthens very slightly (less than 5mm) as you move to 70mm, and lengthens a *lot* (about 40mm) when you move to 24mm.
Yeah, it's weird, but it's a good lens, and in the Minolta AF world, there's really nothing else in that range that comes close in quality.
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All Things Mopar - 13 Jun 2006 01:59 GMT Today, with great enthusiasm and quite emphatically, Dave laid this on an unsuspecting readership ...
> Looking a purchasing a new zoom lense for a rebel xt. I see > some lenses > with a 4X or ~7X zoom equil. How do you calculate the ?X > zoom > factor for a zoom lense? divide the longest focal length in mm by the shortest - voila! zoom ratio! The "equivalent" refers to the smaller frame size for most digital cameras requiring you to convert the focal lenghts you want for your non-full frame digital to their true visual effect when used on a full-frame digital or a 35mm film SLR
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Steve Leo - 14 Jun 2006 00:00 GMT Wouldn't you divide the "normal" lens for your camera (in the case of Full Frame Camera -- 50MM into the longest zoom say 300mm & get 6X zoom? Or in the case of a 1.6 sensor which has a "normal" lens of about 30mm divided into 300mm would give you a 10X zoom. I believe that is what the OP wanted to know. Of course I could be wrong on this.
> Today, with great enthusiasm and quite emphatically, Dave laid > this on an unsuspecting readership ... [quoted text clipped - 10 lines] > for your non-full frame digital to their true visual effect when > used on a full-frame digital or a 35mm film SLR JPS@no.komm - 13 Jun 2006 04:55 GMT >Looking a purchasing a new zoom lense for a rebel xt. I see some lenses > with a 4X or ~7X zoom equil. How do you calculate the ?X zoom >factor for a zoom lense? You divide the longest focal length by the shortest.
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><<> <>>< <>>< ><<> <>>< ><<> ><<> <>>< My Names Nobody - 13 Jun 2006 20:41 GMT > Looking a purchasing a new zoom lense for a rebel xt. I see some lenses > with a 4X or ~7X zoom equil. How do you calculate the ?X zoom factor for > a zoom lense? > > thanks I think that the answers being given aren't answering the question being asked.
OK lets say some simple point and shoot camera (or any camera/lens that is not magnifying/zooming) does not magnify the object you are photographing. We will call this Zero Magnification (What we see with the naked eye?).
The question I want an answer to, is not what the zoom ratio of a lens compared to itself, but rather the number of times that "Zero Magnification" photograph would be "zoomed" multiplied if that photo were taken with a lets say 400mm lens (lets forget the digital crop factor for now, that is an easy equation)?
We all know that a Canon EOS 30D with a 400mm lens zooms in a lot closer (magnifies the object many more times) than say a 12x lens on a Kodak P850.
These point and shoot cameras and big lenses for SLR cameras magnification certainly can be compared, as one would compare small and large binoculars magnification.
Does anyone have any way to calculate a base line "Zoom" factor in this manor rather than comparing the range of a specific lens?
Thanks
madhobbit.geo@yahoo.com - 13 Jun 2006 21:11 GMT > > Looking a purchasing a new zoom lense for a rebel xt. I see some lenses > > with a 4X or ~7X zoom equil. How do you calculate the ?X zoom factor for [quoted text clipped - 4 lines] > I think that the answers being given aren't answering the question being > asked. (...snip...)
> Does anyone have any way to calculate a base line "Zoom" factor in this > manor rather than comparing the range of a specific lens? Sure - but you need to pick a baseline for comparison.
What you're really looking at here is the angle of view - how much of the world in front of you is ending up in the final picture. A very long lens / a very powerful zoom will give you a very small angle of view - a very small amount of the world in fornt of you ends up on the photo, getting "enlarged" in the process.
The two things that affect angle of view are the lens's focal length (measured in mm) and the size of the image sensor or film frame. To make things easier to compare, people often talk about "35mm equivalent" focal length - comparing the focal length to the focal length required to get the same image on a standard 35mm film camera. For instance, a 50mm lens on a 35mm camera is roughly equivalent to a 31mm lens on some DSLR cameras, or an 8.3mm lens on a Canon S3-IS. A site like dpreview.com (and some camera spec sheets) will give you the 35mm equivalent focal lengths for compact cameras: DPReview describes the Canon S3 IS as having a "36-432mm equiv." lens (the actual lens is 6-72mm). The Digital Rebel's 18-55mm kit lens is a 29-88mm equiv. when mounted on a Digital Rebel.
So...once you have 35mm equivalents for all the cameras/lenses you want to compare, you need a baseline to work from (assuming you want numbers of the type "3X"). A reasonable starting place is 50mm - this is generally considered to be a "normal" lens on a 35mm camera.
Working from that: the Canon S3 IS is 432/60 = 8.6X when zoomed in all the way, and 36/50 = 0.7X when zoomed out all the way. The Digital Rebel kit lens, mounted on a Digital Rebel, is 1.8X when zoomed in, and 29/50 = 0.6X when zoomed out.
But really, once you have 35mm equivalents, there's not much benefit to calculating them as numeric "X" factors, especially since they need to be calculated from an arbitrary base point. The equivalent focal lengths alone are all the information you need, and this is why you'll often see them quoted.
- Darryl
My Names Nobody - 13 Jun 2006 21:54 GMT >> > Looking a purchasing a new zoom lense for a rebel xt. I see some >> > lenses [quoted text clipped - 13 lines] > > Sure - but you need to pick a baseline for comparison. (...snip...)
> - Darryl The baseline for comparison is equipment non specific, ZERO magnification, what the naked eye sees.
Why is it that binocular, rifle scope, spotting scope and video camera makers all seem to easily come up with a baseline for comparison, and yet that seems to be near impossible for SLR camera people?
Can't the baseline for comparison be equipment non specific? Say a 1 inch bumble bee (or white square) at 30 feet is 1/32 of an inch at 100% with no magnification (what the naked eye sees). With X lens/camera that same 1 inch bumble bee at 30 feet is 1/2 of an inch at 100% 15X zoom? Or with X lens/camera that same 1 inch bumble bee at 30 feet is 1 foot at 100% 384X zoom?
Then you could rather easily chart that say a 400mm lens is the equivalent to 260X (or whatever it is) zoom on a 35 millimeter camera body (isn't that the de facto camera body baseline anyway?) IE: A 35 millimeter camera body with a 400mm lens is the equivalent to 260X (or whatever it is) zoom.
Seems someone should have already done this?
Does anyone have any way to calculate a equipment non specific, "Zoom" factor in this manor rather than comparing equipment specifics?
DoN. Nichols - 13 Jun 2006 23:49 GMT According to My Names Nobody <nobody@msn.com>:
> >> > Looking a purchasing a new zoom lense for a rebel xt. I see some > >> > lenses [quoted text clipped - 19 lines] > The baseline for comparison is equipment non specific, ZERO magnification, > what the naked eye sees. *Whose* naked eye? The actual size of the image on the retina is a function of the size of the individual eye. You are not seeing a *size* at a distance, but an *angle*.
> Why is it that binocular, rifle scope, spotting scope and video camera > makers all seem to easily come up with a baseline for comparison, and yet > that seems to be near impossible for SLR camera people? Quite simple -- the instruments which you make (other than the video camera) are designed to go in front of human optical equipment (eyes), and they *increase* the size of the image by a specific factor on *anybody's* retina.
And the video cameras are not giving you zoom related to a "normal" view, but rather a ratio between the widest and the narrowest angles of view.
35mm camera lenses, are designed to produce an image on a sensor. Originally film, and those lenses are now being used to form images on the digital sensors of cameras made to accept the same lens mount.
Note that you can't simply hold a telephoto lens in front of your eye and see a larger image. It has to be formed on something, even a virtual image (in air) with a secondary lens to reformat it for feeding into the individual's eye. And if you use the secondary lens, the magnification which you see looking though the combination of the secondary lens and your camera's lens is going to be a function of both the focal length of the camera's lens and the magnification of the eyepiece. (This is equivalent to changing the size of the sensor in the camera.
And photographers who have come to this from the 35mm world have a natural feel for what a given focal length lens will give them, and only have to adjust their expectations for the size of the crop factor for their particular camera.
Now -- there are optical devices for 35mm and DSLR cameras which *are* rated with a magnification factor. Those are telextenders, which go between the body and the lens which you normally use, and they increase the size of the image from a given lens by such a factor. (I think that the most common factors are 1.5X and 2.0X.) In the process, they also reduce the effective maximum aperture of the lens -- you get less light in exchange for greater image size.
> Can't the baseline for comparison be equipment non specific? > Say a 1 inch bumble bee (or white square) at 30 feet is 1/32 of an inch at > 100% with no magnification (what the naked eye sees). 1/32 of an inch on *what*? As I mentioned above, the size of the image on the retina of the eye depends on the physical dimensions of the individual's eye. The one inch bumble bee at 30 feet is not a *size*, it is an angle. In particular, nine minutes, 32 seconds, or 0.1592 degrees in decimal. The size of the image produced from that angle is a function of the focal length of the lens, but "no magnification" is meaningless here. In my previous followup elsewhere in this thread, I explained how you need to pick a standard 50mm for a 35mm film camera) which is close to producing the same angle of view (on a print of a given size, viewed at a specific distance). It is this which defines a "normal" lens for a given sensor. And everything else needs to be compared to that.
> With X lens/camera > that same 1 inch bumble bee at 30 feet is 1/2 of an inch at 100% 15X zoom? > Or with X lens/camera that same 1 inch bumble bee at 30 feet is 1 foot at > 100% 384X zoom? Again -- a function of what you call a "normal" for that camera/sensor.
> Then you could rather easily chart that say a 400mm lens is the equivalent > to 260X (or whatever it is) zoom on a 35 millimeter camera body (isn't that > the de facto camera body baseline anyway?) A 50mm focal length lens is considered by most to be "normal" on a 35mm film camera body. There are others who prefer something somewhere in the range between 42mm and 50mm.
A normal lens on other cameras is a function of the size of the film. IIRC, a "normal" lens on a 2-1/4" square camera (TLR or something like a Hasselblad) is 80mm. The lens which came with my 4x5" Crown Graphic is 135mm -- certainly within the "telephoto" range for 35mm film.
> IE: A 35 millimeter camera body with a 400mm lens is the equivalent to 260X > (or whatever it is) zoom. Actually -- it is closer to an 8X magnification -- when compared to a 50mm lens.
> Seems someone should have already done this? It seems to me that the normal users of SLRs have found that the existing information -- the actual focal length range of the zoom -- is much more usable information.
And remember that the built-in zoom lenses in digital cameras are rated not in magnification relative to "normal", but rather magnification change from widest to narrowest field of view.
> Does anyone have any way to calculate a equipment non specific, "Zoom" > factor in this manor rather than comparing equipment specifics? You *must* include equipment specifics to get the kind of number which you are looking for. Anything else is meaningless.
Enjoy, DoN.
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Jeremy Nixon - 14 Jun 2006 00:07 GMT > Why is it that binocular, rifle scope, spotting scope and video camera > makers all seem to easily come up with a baseline for comparison, and yet > that seems to be near impossible for SLR camera people? It's not impossible, it's just not a useful metric, so no one does it.
> Can't the baseline for comparison be equipment non specific? Yes, it can, but for YOU to figure out the optical magnification given a lens and camera spec, you need to define 1x magnification in terms of something you know. So you start with the "normal" lens focal length for the format, which is 1x magnification, and then you can figure out the magnification factor provided by a given focal length.
> Then you could rather easily chart that say a 400mm lens is the equivalent > to 260X (or whatever it is) zoom on a 35 millimeter camera body (isn't that > the de facto camera body baseline anyway?) > IE: A 35 millimeter camera body with a 400mm lens is the equivalent to 260X > (or whatever it is) zoom. Camera lenses are *never* specified with that kind of magnification factor, so no, you can't do that kind of comparison. When a P&S camera is said to have a "10x zoom", that does *not* mean 10x magnification; it means that the longest focal length is 10x the shortest focal length.
If you do the above procedure to figure out the optical magnification, the resulting number is not useful for comparison with any camera's zoom specs.
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madhobbit.geo@yahoo.com - 14 Jun 2006 01:06 GMT > >> Does anyone have any way to calculate a base line "Zoom" factor in this > >> manor rather than comparing the range of a specific lens? [quoted text clipped - 9 lines] > makers all seem to easily come up with a baseline for comparison, and yet > that seems to be near impossible for SLR camera people? Because you look through a telescope, but you print out a photo. When I look through a pair of binoculars, I am enlarging the image on my retina, to be (say) 10x the size of the original. "Huh," I say, "these binoculars have 10x magnification."
But when I take a picture, I can print it at wallet size, or 4x6, or 8x10, or 20x30. I can look at it from six inches away or from the other side of the room. Every time I do that, the image changes size on my retina, occupying more (or less) of my field of view.
Now, this doesn't mean you can't define a 1x magnification. I could (watch me!) arbitrarily say that "A 1x lens will allow me to take a photo of a tree, print it out at 8"x10", hold it in landscape orientation at arm's length, and have the resulting image look exactly the same size as it did when I was standing there."
No problem; we can do that. Assuming your arm is one metre long, that 10" wide photo is going to take up about 10 degrees of your field of view ( atan(17.5 cm / 100 cm) = 9.93 degrees ). So, if the camera lens had a 10 degree field of view, I should be able to print out the picture, hold it in front of me, and have it blend seamlessly into the surroundings. Tada, it's 1x magnification! As it turns out, a 200mm lens on a 35mm camera has about a 10-degree field of view, so without further ado:
A 200mm lens on a 35mm camera is a 1x lens A 50mm lens on a 35mm camera is a 0.25x lens A 200mm lens on a 35mm camera is a 1.5x lens A 18mm lens on a APS-C camera is a 0.14x lens A 6mm lens on a Canon S3 IS is a 0.18x lens
As it turns out, these are pretty silly numbers; more less than 1x than greater. So apparantly I picked bad assumptions; maybe assuming an 11x14 print at half a meter would have given me numbers more in line with what we're looking for.
But that's the problem right there. The size of the print, and the distance at which the print is viewed, changes the apparant magnification of the image. A telescope doesn't have this problem: You look through it, and your eye is always in the same place with respect to the lens. Nothing changes size, nothing changes distance.
That doesn't mean it's not possible; I've just proven that it is. But it's arbitrary. Change the assumptions you make about print size and viewing distance, and you change the magnification numbers you get. And when you examine the process, you realize that all those assumptions did is tell me that a 200mm lens on a 35mm camera is 1x, and all the other calculations were made off of that. This is exactly what I originally suggested: You need to pick a baseline for comparison. My original choice of a 50mm lens on a 35mm camera was based on a common photographic tradition; my new choice is based on some calculations made from arbitrary assumptions.
So instead, we measure lens magnification based on the lens's focal length. This is an inherent property of the lens. A 35mm photographer will know that a 100mm lens makes things big and a 28mm lens makes things small. As odd-sized digital sensors got common, the idea of a "35mm equivalent" focal length gained popularity, exactly so that people had a good non-ambiguous way of understanding the optical effects of their lenses when combined with their cameras.
> Can't the baseline for comparison be equipment non specific? Not really; if nothing else, the camera is important. I have a 50mm lens that I use on my Digital Rebel. If I took a picture with it, and then gave the lens to my sister, she could take a picture with it with her 35mm film camera from the same location, and when we printed the pictures, hers would look more "zoomed out" than mine. Canon can't stamp a big "1x" on the side of the lens, because it's going to behave differently depending on the camera you put behind it. But they can engrave "50mm" on the lens; that never changes, and it's up to the photographer to understand what that means when it's combined with his or her camera.
Looking at it another way: 35mm equivalent focal lengths -are- equipment non-specific. Every lens/body combination has a 35mm equivalent focal length, which describes exactly how much "zoom" you will get. Why 35mm? Why not? Most photographers are familiar with it, and those that aren't can learn it or convert it to some system they know better (like APS-C equivalent, or angle-of-view-when-printed-at-8-x-10-and-held-a-meter-away equivalent).
> Say a 1 inch bumble bee (or white square) at 30 feet is 1/32 of an inch at > 100% with no magnification (what the naked eye sees). With X lens/camera > that same 1 inch bumble bee at 30 feet is 1/2 of an inch at 100% 15X zoom? This goes back to the bulk of my response, up above: 1/2 an inch on what size print? On the film negative (or digital sensor) itself? The frame is rather small, and is almost always enlarged to at least some degree before you actually look at it.
> Then you could rather easily chart that say a 400mm lens is the equivalent > to 260X (or whatever it is) zoom on a 35 millimeter camera body (isn't that > the de facto camera body baseline anyway?) It's only the common baseline among people that use 35mm cameras, compact digital cameras, and DSLRs. Talk to a medium- or large-format photographer (I am neither) and I'd be very surprised if they use 35mm equivalents when discussing their lenses.
> Seems someone should have already done this? I just did, results are above, free for the world to use :-) I think they suck, though. Really, 200mm as a 1x lens? That's just silly. Improvement on this is left as an exercise for the reader...
> Does anyone have any way to calculate a equipment non specific, "Zoom" > factor in this manor rather than comparing equipment specifics? I've only seen this in one photographic context: Macro lenses. They're commonly quoted as being 0.5x (low-end ones), 1x (most decent ones), and I've seen as high as 5x. This is comparing the size of the object in real life to the size of the image on the film/sensor. This means, though, that when a print is made from a picture taken with a 1x macro lens, the image on the print will be larger than the object actually is in reality. The 1x is very counterintuitive here. They're also described as ratios (e.g. 1:2, 1:1, 5:1), possibly to try to avoid exactly this confusion.
- Darryl
Marc Sabatella - 14 Jun 2006 02:52 GMT > The baseline for comparison is equipment non specific, ZERO > magnification, what the naked eye sees. That might be the baseline *you'd* like to use for comparison, but it is *not* the baseline actually used when you see cameras with zoom lenses quote magnification ratios. A point & shoot camera that advertises a "7X" zoom is not saying that it magifies things seven times more than "what the naked eye sees", but rather, that its maximum magnification is seven times its minimum magnification. Most likely, the minimum magnification is a little more than half "what the naked eye sees" (to the extent it makes sense to define this at all - see below), and the maximum magnification three to four times "what the naked eye sees". Whereas another zoom lens might be only "4X", but that might mean minimum is twice "what the naked eye sees" and the maximum is eight times "what the naked eye sees". Meaning the 4X zoom would actually magnify more than the 7X. That's why you don't see SLR lenses using ratios like these. You see real, hard numbers to give focal length. The 7X zoom I mentioned would actually be sold as 28-200, the 4X as 100-400. Then we could compare the focal length ranges directly to see that the former did a lot more at the wide angle end of the range but the latter did a lot more at the telephoto end. This is all relevant information, and that's why camera lenses are labelled with all of it.
> Why is it that binocular, rifle scope, spotting scope and video camera > makers all seem to easily come up with a baseline for comparison, and > yet that seems to be near impossible for SLR camera people? Video camera zoom ratios are exactly like point & shoot zoom ratios. That is, they aren't telling you how much a camera magifies comared to what the naked eye sees, but simply telling how its maximum magnification compares to its minimum magnification. As for binoculars and scopes, it is possible to come up with a definitive number for these because the images are being projected on the same screen: your retina. Now, if you want to take the lens off your camera and hold it up to your eye like a telescope, you could similar come up with an absolute number to measure the magnification. But that number would only be meaningful when projecting the image onto your retina. It would cease to have meaning when projecting the image onto a piece of film or a camera sensor. Because in order for that image to eventually get on to your retina, it's going to have to be displayed or printed somehow, and you have no way of knowing how much it is going to be magnified in the process of displaying or printing it.
> Can't the baseline for comparison be equipment non specific? Not really, at least, not in the way you want. See below. The best convention we have is that of a "normal" lens, which as has been mentioned here, is considered around 50mm on a 35mm film camera, or around 30-35mm on most digital SLR's. What is relevant in making this "normal" isn't so much magnification, since any picture can be blown up bigger, but rather, angle of view - how much you can actually take in at once without moving your eyes. A normal lens is one that approximates the angle of view that we typically see. Of course, that differs between people, and since our vision isn't constant across our field of view but rather drops off toward the edges (and at different rates for things close up than things far away, most likely), there is some leeway in defining even for a given person what his angle of view is. But there is general agreement that somewhere around 50mm is a "normal" focal length for most people when projecting an image onto a piece of 35mm film. And since most digital sensors are smaller than that, a correspondingly smaller focal length is "normal". Of course, it order for that image to actually *look* normal, we'd have to project them onto a wall that just barely fills out field of vision. When looking at the image printed 4x6, we sort of have an inutive sense of what looks "normal" and what looks like it was taken with a longer or shorter focal length length, but this can be deceiving. It can be hard to tell the difference between an object taken with a 50mm from 10 feet away versus the same object taken with a 200mm from 40 feet away (actually, I'm not sure I have the math right there - it might be 20 feet, or some other number involving the square root of 2, to get the object to appear the same size on a same sized print, but whatever). Still, the notion of a "normal" lens is the closest you're going to get to "what the naked eye sees".
So if you want to compute a "magification" factor in this way, divide the focal length by, say, 33 for most digital SLR's or 50 for a 35mm film SLR or "full frame" digital. Thus, the aforementioned 28-200 zoom would not be called a "7X" zoom, but rather, a ".6X - 4X" zoom on a 35mm camera, or a ".8X - 6X" on most digital SLR's. That is, you'd list the magnifications at both ends of the zoom range, not just the ratio between those magnifications. And indeed, one *could* do this. But I'm not sure I have any intuitve sense of what ".6X" or "4X" looks like. The only way to know would be get a feel for it through experience. And one can develop a feel for what "200mm" looks like just as surely as one can what "4X" looks like. So I don't see what is gined by this approach.
> Say a 1 inch bumble bee (or white square) at 30 feet is 1/32 of an > inch at 100% with no magnification (what the naked eye sees). 1/32 of an inch where? On your retina? If you hold out a ruler at arm's length? This is problem #1 with computing what sort of magnification we are talking about in absolute terms.
> With X lens/camera that same 1 inch bumble bee at 30 feet is 1/2 of > an inch at 100% 15X zoom? 1/2 an inch where? On the camera sensor? When you display it on your comuter screen? When you make a 4x6 print? When you project it on a wall? That's problem #2 with computing what sort of magification we are talking about in absolute terms.
> Does anyone have any way to calculate a equipment non specific, "Zoom" > factor in this manor rather than comparing equipment specifics? No, because such a thing is quite impossible to do for the reasons described. Howeve,r it is trivially simple to divde focal length by 50 or 33 to get something resembling what you are talking about if calling a 200mm lens a "4X" zoom has more meaning to you than simply calling it a 200mm lens.
--------------- Marc Sabatella marc@outsideshore.com
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DoN. Nichols - 13 Jun 2006 21:28 GMT According to My Names Nobody <nobody@msn.com>:
> > Looking a purchasing a new zoom lense for a rebel xt. I see some lenses > > with a 4X or ~7X zoom equil. How do you calculate the ?X zoom factor for [quoted text clipped - 24 lines] > Does anyone have any way to calculate a base line "Zoom" factor in this > manor rather than comparing the range of a specific lens? Well ... a so-called "normal" lens on full-frame 35mm is a 50mm (or close to that), so you can calculate the number you want by dividing 50 into 400, giving a "magnification factor" of 8.
However, for a Nikon digital SLR, with a crop factor of 1.5, a "normal" lens would be about 33.3mm, so that, divided into 400 would give a magnification factor of 12, on *that* camera.
Since the Cannon seems to more often have a crop factor of 1.6, on that camera, a "normal" lens would be closer to 31.25mm, and that, dividied into 400mm would give a magnification factor of 12.8
Of course, this makes a 50mm lens on a Nikon DSLR a mild telephoto (giving you the 1.5 crop factor as the magnification factor.)
So -- you have to re-calculate it for each sensor size.
But -- you have the tools above to allow you to do so for each camer and lens combination you come across.
I hope that this helps, DoN.
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Dr. Boggis - 13 Jun 2006 22:30 GMT > > Looking a purchasing a new zoom lense for a rebel xt. I see some lenses > > with a 4X or ~7X zoom equil. How do you calculate the ?X zoom factor for [quoted text clipped - 8 lines] > not magnifying/zooming) does not magnify the object you are photographing. > We will call this Zero Magnification (What we see with the naked eye?). No magnification would be magnification x1, surely? If it's zero times the amount you see with the naked eye, you'd see nothing :-P
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My Names Nobody - 14 Jun 2006 00:48 GMT >> > Looking a purchasing a new zoom lense for a rebel xt. I see some >> > lenses [quoted text clipped - 15 lines] > No magnification would be magnification x1, surely? If it's zero times > the amount you see with the naked eye, you'd see nothing :-P Zero times? I wrote zero magnification, not zero times. As defined by the dictionary, zero magnification is correct, surely?
magnification noun 1 The act of magnifying or the state of being magnified. 2 The process of enlarging the size of something, as an optical image. 3 Something that has been magnified; an enlarged representation, image, or model. 4 The ratio of the size of an image to the size of an object. 5 A photographic print that has been enlarged
zero noun 1 A cardinal number indicating the absence of any or all units under consideration 2 An ordinal number indicating an initial point or origin Zero magnification means just what is says, What we see with the naked eye is not magnified, not enlarged.
Can you add any input as to a way to calculate a universal, equipment non specific, "Zoom" factor?
madhobbit.geo@yahoo.com - 14 Jun 2006 01:19 GMT > > No magnification would be magnification x1, surely? If it's zero times > > the amount you see with the naked eye, you'd see nothing :-P [quoted text clipped - 4 lines] > Zero magnification means just what is says, What we see with the naked eye > is not magnified, not enlarged. Well, to have any type of coherent discussion, it's pretty important to agree on the basic terms.
Magnification is a ratio. 1:1 magnification is no magnification; the final image is the same size as the starting image. 2:1 magnification makes the final image twice as big as the initial image, etc. Those ratios are equivalent to magnification factors of 1.0 and 2.0; a magnification of 1.0, or 1:1, or 1x, or however you write it, is indeed "no magnification".
The problem with writing "zero magnification" is that, while it's perfectly valid on its own (i.e. it's synonymous with "no magnification"), the usage of a number opens the door to potential confusion. The phrase "0.5 magnification" is commonly understood to mean "half the size"...this raises the question of what "0 magnification" should be.
The phrase "zero magnification" has a perfectly valid meaning according to the strict dictionary definition, but in this context something like "1x magnification" or "no magnification" is less likely to cause confusion.
- Darryl
Nancy - 12 Jul 2006 03:57 GMT > > > No magnification would be magnification x1, surely? If it's zero times > > > the amount you see with the naked eye, you'd see nothing :-P [quoted text clipped - 28 lines] > > - Darryl Nancy - 12 Jul 2006 03:59 GMT > > > No magnification would be magnification x1, surely? If it's zero times > > > the amount you see with the naked eye, you'd see nothing :-P [quoted text clipped - 28 lines] > > - Darryl Could you please explain how a 120-300mm lens can have a magnification factor of 1;6
G.T. - 12 Jul 2006 05:49 GMT >>>>No magnification would be magnification x1, surely? If it's zero times >>>>the amount you see with the naked eye, you'd see nothing :-P [quoted text clipped - 31 lines] > Could you please explain how a 120-300mm lens can have a magnification > factor of 1;6 It can't.
Greg
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DoN. Nichols - 13 Jul 2006 05:52 GMT According to G.T. <getnews1@dslextreme.com>:
[ ... ]
> > Could you please explain how a 120-300mm lens can have a magnification > > factor of 1;6 > > It can't. Well ... it *can* -- depending on what system it is mounted on.
If the "normal" lens for that system is a 50mm, then the *maximum* zoom of this lens on this camera is 6:1 compared to the *normal* lens only. And -- at its *minimum* zoom, it is offering a 2.4:1 ratio, again compared to the camera's normal lens.
However, the zoom lens covers a zoom *range* of 2.5:1 comparing its shortest focal length to its longest focal length -- and since this figure is relative to itself, the figure is independent of the normal lens of the camera on which you may choose to mount it.
Enjoy, DoN.
P.S. I though that this thread had already burned out some time ago. :-)
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Nancy - 13 Jul 2006 16:46 GMT > > > No magnification would be magnification x1, surely? If it's zero times > > > the amount you see with the naked eye, you'd see nothing :-P [quoted text clipped - 28 lines] > > - Darryl Can you explain why the magnification ratio on a 120-300mm lens is listed at 1:6?
J. Clarke - 13 Jul 2006 17:22 GMT >> > > No magnification would be magnification x1, surely? If it's zero >> > > times the amount you see with the naked eye, you'd see nothing :-P [quoted text clipped - 31 lines] > Can you explain why the magnification ratio on a 120-300mm lens is > listed at 1:6? At the closest focus of which the lens is capable without additional components such as extension tubes or bellows it can put an image on the sensor that is 1/6 the size of the actual subject. It may be able to do this at all focal lengths or at a range of focal lengths or only at one focal length depending on the details of the design.
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Dave - 14 Jun 2006 03:05 GMT > Looking a purchasing a new zoom lense for a rebel xt. I see some lenses > with a 4X or ~7X zoom equil. How do you calculate the ?X zoom factor > for a zoom lense? Sorry for stirring the pot. Here is my situation. My wife and her brother weee taking the same pic from the same spot of the same bird on a rock. She has her new XT with a long 200 mm lense and her brother had I think a S2IS. When they compared pics on the computer his were much closer. She wants to know how long a lense would be needed to match his 10X on his point and click.
I was also wonder if the 1.6x had anything to do with the calculation.
thanks and sorry again.
madhobbit.geo@yahoo.com - 14 Jun 2006 03:26 GMT > Sorry for stirring the pot. Here is my situation. My wife and her > brother weee taking the same pic from the same spot of the same bird on [quoted text clipped - 4 lines] > > I was also wonder if the 1.6x had anything to do with the calculation. Ah, well that's quite easy. All you need to do is find out the 35mm equivalent focal length of the S2IS, and then convert that to a focal length for the Rebel XT.
So, looking at Canon's site: the S2 IS (assuming that's what it was) has a 6-72mm lens, which is listed as equivalent to a 36-432mm lens on a 35mm camera.
(Those numbers come from http://www.usa.canon.com/consumer/controller?act=ModelTechSpecsAct&fcategoryid=1 44&modelid=11368)
This means that on a 35mm camera, you'd need a 432mm lens to get the same effect as the S2 IS at full magnification. The 1.6x factor does, indeed, come into play: On a Rebel XT, you'd want a 432mm / 1.6 = 270mm lens to get that effect.
So, this matches perfectly with your observations: The 200mm lens your wife has is shorter than 270mm, so the picture will appear farther away. You won't find a 270mm lens, but a 300mm lens would do the trick nicely; Canon makes a few lenses that would fit the bill. Disappointing as it may seem, the S2 IS has a longer reach than the Rebel XT with a 200mm lens. (Of course, you can mimic this by cropping the picture; you can probably get a perfectly acceptable print that way).
Of course, assuming you have the 18-55mm kit lens...that's a 35mm equivalent of 18 * 1.6 = 29mm at the wide end, and the S2 IS is only a 36mm equivalent at the wide end, so with that lens your wife's camera will have a better wide-angle lens than the S2 IS. (For some reason, point-and-shoot digital cameras seem to be quite powerful on the long end but lacking on the wide angle; I don't know if this is purely marketing or if there's some good optical reason for this).
> thanks and sorry again. No need to apologize - the nature of Usenet is such that you have a bunch of people sitting around just waiting to get into incredibly convolved discussions about something, anything :-)
Jeff Rife - 14 Jun 2006 06:46 GMT (madhobbit.geo@yahoo.com) wrote in rec.photo.digital.slr-systems:
> Disappointing > as it may seem, the S2 IS has a longer reach than the Rebel XT with a > 200mm lens. (Of course, you can mimic this by cropping the picture; you > can probably get a perfectly acceptable print that way). Grinding out the math shows that it's pretty much identical.
The full sensor of the S2 IS has 2592x1944 pixels. The crop area from the Rebel XT with the 200mm lens will be 2566x1711. OK, so I'm a geek... sue me.
This works because the Rebel XT is 8MP and the 200mm lens the OP has isn't too far off the 270 needed. On pixel count alone, if the OP only had a 100mm lens, they'd be better off using the S2 IS instead of cropping from the Rebel XT.
I had already been thinking about this same sort of thing when I was wondering if a camera with a 35mm-sized sensor would be worth the loss of the extra reach of telephotos on a APS-C sensor camera. You need 2.25 times the pixels to make the crop equivalent, so if you have a 10MP APS-C camera, you really can't find a 35mm-sized sensor that comes close to enough pixels to do this.
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G.T. - 14 Jun 2006 08:10 GMT >> Looking a purchasing a new zoom lense for a rebel xt. I see some >> lenses with a 4X or ~7X zoom equil. How do you calculate the ?X [quoted text clipped - 8 lines] > > I was also wonder if the 1.6x had anything to do with the calculation. Yes, it does. Aside from that if she got a 1.4x teleconverter for her 200mm lens then she's going to be pretty close to the S2 IS. If it's the Canon 55-200 then she should probably just get a new lens.
Greg
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J. Clarke - 14 Jun 2006 12:22 GMT >> Looking a purchasing a new zoom lense for a rebel xt. I see some lenses >> with a 4X or ~7X zoom equil. How do you calculate the ?X zoom factor [quoted text clipped - 10 lines] > > thanks and sorry again. Canon states that the S2 has a 35mm-equivalent focal length of 432mm. Divide that by the 1.6 crop factor of the XT and you get 270 for the equivalent field of view on the XT. So a 300 should do nicely, or a 200 on a 1.4x telextender.
The "4x" or "7x" is the range from longest to widest, not the overall magnification. A 10-70 and a 100-700 would both be "7x".
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J. Clarke - 13 Jul 2006 14:49 GMT > Looking a purchasing a new zoom lense for a rebel xt. I see some lenses > with a 4X or ~7X zoom equil. How do you calculate the ?X zoom > factor for a zoom lense? I see the usual bunch of wrong information has been posted.
If a zoom lens is sold as "4x" or "7x" that's generally just the longest focal length divided by the shortest. An 18-200mm lens for example would have a zoom ratio of 11.1x (200 / 18), while a 10-22 would have a zoom ratio of 2.2x and the popular 17-85 would have 5x. The important numbers to look at are the longest and shortest focal lengths and the aperture, not the zoom ratio.
Now, some folks have gone off the deep end about magnification. When you are talking about binoculars then the 7x or 10x or whatever refers to the magnification relative to what is seen with the naked eye. Photographic lenses aren't generally described in that manner. Instead magnification will generally be expressed as a ratio of image size to subject size, so for example a lens than can do 1:6 would be able to put an image on the sensor that was 1/6 the size of the subject, while one that could go 6:1 would be able to put an image on the sensor that is 6 times the size of the subject. It would not however be sold as a "6x zoom". In fact magnification is determined by the ratio of distance to sensor vs distance to subject and is only indirectly affected by zoom ratio. Just about any lens can achieve high magnifications with the proper accessories--what will change is the sharpness and the distance to the subject at which a given magnification will be achieved--there will also be a limiting value that occurs when the lens comes in physical contact with the subject.
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